Exercises 2 - if else

FizzBuzz is a common programming problem https://en.wikipedia.org/wiki/Fizz_buzz used to practice if statements and division.

For our version, create a vector test_vec of the numbers 1 to 50 (1:50). Then apply the following rules using dplyr::if_else statements to obtain the appropriate behavior:

• if the number is divisible by 3, output “Fizz”
• if the number is divisible by 5, output “Buzz”
• if the number is divisible by 15, output “FizzBuzz”
• otherwise, return the number as a character (as.character())

Notes:

• %% will give the remainder or a division (for instance 15 %% 3 is 0 and 16 %% 3 is 1). You can use this function and check if the remainder is 0.
• You have to start with checking 15 and then you can do 5 or 3 after that.

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